Goで時間を比較する際の注意点

Problem

I forgot to be multipled by “time.Second”, when I compared the elapsed time with which I specific, such as sndT.Sub(fstT) > time.Duration(10).

Which you can know how to be occured

package main import ( "log" "time" ) func main() { fstT := time.Now() log.Println("fstT: ", fstT) sndT := time.Now().Add(time.Duration(5) * time.Second) log.Println("sndT: ", sndT) if sndT.Sub(fstT) > time.Duration(10) { log.Println("time.Duration(10) is ", time.Duration(10), ", unit is 'ns', this is why you pass through this condition.") } if !(sndT.Sub(fstT) > time.Duration(10)*time.Second) { log.Println("You have to be multiplied by 'time.Second' to become second(s) unit.") } }

Output

2009/11/10 23:00:00 fstT: 2009-11-10 23:00:00 +0000 UTC m=+0.000000001 2009/11/10 23:00:00 sndT: 2009-11-10 23:00:05 +0000 UTC m=+5.000000001 2009/11/10 23:00:00 time.Duration(10) is 10ns , unit is 'ns', this is why you pass through this condition. 2009/11/10 23:00:00 You have to be multiplied by 'time.Second' to become second(s) unit.